Base | Representation |
---|---|
bin | 11010011111010100… |
… | …11101100100011001 |
3 | 1100201010010122200221 |
4 | 31033222131210121 |
5 | 213111141324423 |
6 | 10311102400041 |
7 | 1012264121056 |
oct | 151752354431 |
9 | 40633118627 |
10 | 14221433113 |
11 | 60386a0208 |
12 | 290a890021 |
13 | 145845b9a4 |
14 | 98ca7802d |
15 | 5837c2e5d |
hex | 34fa9d919 |
14221433113 has 8 divisors (see below), whose sum is σ = 15142114080. Its totient is φ = 13310099520.
The previous prime is 14221433099. The next prime is 14221433119. The reversal of 14221433113 is 31133412241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14221433113 - 229 = 13684562201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14221433119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2333703 + ... + 2339788.
It is an arithmetic number, because the mean of its divisors is an integer number (1892764260).
Almost surely, 214221433113 is an apocalyptic number.
It is an amenable number.
14221433113 is a deficient number, since it is larger than the sum of its proper divisors (920680967).
14221433113 is a wasteful number, since it uses less digits than its factorization.
14221433113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4673687.
The product of its digits is 1728, while the sum is 25.
Adding to 14221433113 its reverse (31133412241), we get a palindrome (45354845354).
The spelling of 14221433113 in words is "fourteen billion, two hundred twenty-one million, four hundred thirty-three thousand, one hundred thirteen".
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