Base | Representation |
---|---|
bin | 1000010001110010111… |
… | …1110010011001110011 |
3 | 111121002021220000101100 |
4 | 2010130233302121303 |
5 | 4312224322210120 |
6 | 145155550535443 |
7 | 13163151561024 |
oct | 2043457623163 |
9 | 447067800340 |
10 | 142216210035 |
11 | 5534a385589 |
12 | 2368bb07583 |
13 | 10545a7a993 |
14 | 6c51ac8c4b |
15 | 3a75591490 |
hex | 211cbf2673 |
142216210035 has 24 divisors (see below), whose sum is σ = 246525879600. Its totient is φ = 75843173952.
The previous prime is 142216209991. The next prime is 142216210121. The reversal of 142216210035 is 530012612241.
142216210035 is a `hidden beast` number, since 1 + 4 + 2 + 2 + 1 + 621 + 0 + 0 + 35 = 666.
It is not a de Polignac number, because 142216210035 - 227 = 142081992307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142216209990 and 142216210008.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 560641 + ... + 773789.
It is an arithmetic number, because the mean of its divisors is an integer number (10271911650).
Almost surely, 2142216210035 is an apocalyptic number.
142216210035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
142216210035 is a deficient number, since it is larger than the sum of its proper divisors (104309669565).
142216210035 is a wasteful number, since it uses less digits than its factorization.
142216210035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 227987 (or 227984 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 142216210035 its reverse (530012612241), we get a palindrome (672228822276).
The spelling of 142216210035 in words is "one hundred forty-two billion, two hundred sixteen million, two hundred ten thousand, thirty-five".
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