Base | Representation |
---|---|
bin | 1100111011111000111010… |
… | …1110101011111101110011 |
3 | 1212100201010111200221101220 |
4 | 3032332032232223331303 |
5 | 3331012232004223220 |
6 | 50125545334200123 |
7 | 2665402655322300 |
oct | 316761656537563 |
9 | 55321114627356 |
10 | 14223031320435 |
11 | 4593a54428803 |
12 | 17186284b3043 |
13 | 7c22c297a282 |
14 | 3725812720a7 |
15 | 199e912bc540 |
hex | cef8ebabf73 |
14223031320435 has 96 divisors (see below), whose sum is σ = 26927565350400. Its totient is φ = 6390180679680.
The previous prime is 14223031320403. The next prime is 14223031320493. The reversal of 14223031320435 is 53402313032241.
It is not a de Polignac number, because 14223031320435 - 25 = 14223031320403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14223031320396 and 14223031320405.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 185954250 + ... + 186030720.
It is an arithmetic number, because the mean of its divisors is an integer number (280495472400).
Almost surely, 214223031320435 is an apocalyptic number.
14223031320435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14223031320435 is a deficient number, since it is larger than the sum of its proper divisors (12704534029965).
14223031320435 is a wasteful number, since it uses less digits than its factorization.
14223031320435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80841 (or 80834 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 14223031320435 its reverse (53402313032241), we get a palindrome (67625344352676).
The spelling of 14223031320435 in words is "fourteen trillion, two hundred twenty-three billion, thirty-one million, three hundred twenty thousand, four hundred thirty-five".
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