Base | Representation |
---|---|
bin | 10100101100101001011… |
… | …110110010100000010101 |
3 | 12000222021122001000111211 |
4 | 110230221132302200111 |
5 | 141300413002041041 |
6 | 3005224234301421 |
7 | 204521444321320 |
oct | 24545136624025 |
9 | 5028248030454 |
10 | 1422330112021 |
11 | 4a92302a4a25 |
12 | 1ab7a7587871 |
13 | a4181c6a900 |
14 | 4cbac15b7b7 |
15 | 26ee8749481 |
hex | 14b297b2815 |
1422330112021 has 12 divisors (see below), whose sum is σ = 1760178601632. Its totient is φ = 1125360087696.
The previous prime is 1422330112013. The next prime is 1422330112051. The reversal of 1422330112021 is 1202110332241.
It is not a de Polignac number, because 1422330112021 - 23 = 1422330112013 is a prime.
It is a super-4 number, since 4×14223301120214 (a number of 50 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1422330111983 and 1422330112001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1422330112051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 601152711 + ... + 601155076.
It is an arithmetic number, because the mean of its divisors is an integer number (146681550136).
Almost surely, 21422330112021 is an apocalyptic number.
It is an amenable number.
1422330112021 is a deficient number, since it is larger than the sum of its proper divisors (337848489611).
1422330112021 is a wasteful number, since it uses less digits than its factorization.
1422330112021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1202307820 (or 1202307807 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1422330112021 its reverse (1202110332241), we get a palindrome (2624440444262).
It can be divided in two parts, 1422330 and 112021, that added together give a palindrome (1534351).
The spelling of 1422330112021 in words is "one trillion, four hundred twenty-two billion, three hundred thirty million, one hundred twelve thousand, twenty-one".
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