Base | Representation |
---|---|
bin | 1100111011111010010101… |
… | …1111000111010111011111 |
3 | 1212100202010010010002011201 |
4 | 3032332211133013113133 |
5 | 3331014022224124320 |
6 | 50130051253300331 |
7 | 2665415302446115 |
oct | 316764537072737 |
9 | 55322103102151 |
10 | 14223413114335 |
11 | 459412a999157 |
12 | 17187143346a7 |
13 | 7c2353ab5b19 |
14 | 3725b9c57ab5 |
15 | 199eb4a8670a |
hex | cefa57c75df |
14223413114335 has 8 divisors (see below), whose sum is σ = 17068121275680. Its totient is φ = 11378713465824.
The previous prime is 14223413114329. The next prime is 14223413114369. The reversal of 14223413114335 is 53341131432241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14223413114335 - 235 = 14189053375967 is a prime.
It is a super-4 number, since 4×142234131143354 (a number of 54 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14223413114294 and 14223413114303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2438406 + ... + 5864524.
It is an arithmetic number, because the mean of its divisors is an integer number (2133515159460).
Almost surely, 214223413114335 is an apocalyptic number.
14223413114335 is a deficient number, since it is larger than the sum of its proper divisors (2844708161345).
14223413114335 is an equidigital number, since it uses as much as digits as its factorization.
14223413114335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4256417.
The product of its digits is 103680, while the sum is 37.
Adding to 14223413114335 its reverse (53341131432241), we get a palindrome (67564544546576).
The spelling of 14223413114335 in words is "fourteen trillion, two hundred twenty-three billion, four hundred thirteen million, one hundred fourteen thousand, three hundred thirty-five".
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