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14223442101001 = 72031920300143
BaseRepresentation
bin1100111011111010011100…
…1101101100001100001001
31212100202012010122202101221
43032332213031230030021
53331014102134213001
650130054210442041
72665416104024260
oct316764715541411
955322163582357
1014223442101001
114594145297281
121718721b93321
137c2359ac47b3
143725bda415d7
15199eb73b01a1
hexcefa736c309

14223442101001 has 4 divisors (see below), whose sum is σ = 16255362401152. Its totient is φ = 12191521800852.

The previous prime is 14223442100993. The next prime is 14223442101053. The reversal of 14223442101001 is 10010124432241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14223442101001 - 23 = 14223442100993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14223442101061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1015960150065 + ... + 1015960150078.

It is an arithmetic number, because the mean of its divisors is an integer number (4063840600288).

Almost surely, 214223442101001 is an apocalyptic number.

It is an amenable number.

14223442101001 is a deficient number, since it is larger than the sum of its proper divisors (2031920300151).

14223442101001 is an equidigital number, since it uses as much as digits as its factorization.

14223442101001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2031920300150.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14223442101001 its reverse (10010124432241), we get a palindrome (24233566533242).

The spelling of 14223442101001 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-two million, one hundred one thousand, one".

Divisors: 1 7 2031920300143 14223442101001