Base | Representation |
---|---|
bin | 1100111011111100101001… |
… | …1000111001000110010111 |
3 | 1212100210201021002220221202 |
4 | 3032333022120321012113 |
5 | 3331021304223140043 |
6 | 50130232531303115 |
7 | 2665436531103224 |
oct | 316771230710627 |
9 | 55323637086852 |
10 | 14224032240023 |
11 | 459441841a481 |
12 | 171886774aa9b |
13 | 7c2422149b98 |
14 | 37263817c94b |
15 | 199eee0d11b8 |
hex | cefca639197 |
14224032240023 has 4 divisors (see below), whose sum is σ = 14224544421048. Its totient is φ = 14223520059000.
The previous prime is 14224032240001. The next prime is 14224032240037. The reversal of 14224032240023 is 32004223042241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14224032240023 - 26 = 14224032239959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14224032240053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256048853 + ... + 256104398.
It is an arithmetic number, because the mean of its divisors is an integer number (3556136105262).
Almost surely, 214224032240023 is an apocalyptic number.
14224032240023 is a deficient number, since it is larger than the sum of its proper divisors (512181025).
14224032240023 is an equidigital number, since it uses as much as digits as its factorization.
14224032240023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 512181024.
The product of its (nonzero) digits is 18432, while the sum is 29.
Adding to 14224032240023 its reverse (32004223042241), we get a palindrome (46228255282264).
The spelling of 14224032240023 in words is "fourteen trillion, two hundred twenty-four billion, thirty-two million, two hundred forty thousand, twenty-three".
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