14224100000133 has 4 divisors (see below), whose sum is σ = 18965466666848. Its totient is φ = 9482733333420.

The previous prime is 14224100000119. The next prime is 14224100000161. The reversal of 14224100000133 is 33100000142241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14224100000133 - 2⁸ = 14224099999877 is a prime.

It is a super-2 number, since 2×14224100000133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14224100000183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2370683333353 + ... + 2370683333358.

It is an arithmetic number, because the mean of its divisors is an integer number (4741366666712).

Almost surely, 2^{14224100000133} is an apocalyptic number.

It is an amenable number.

14224100000133 is a deficient number, since it is larger than the sum of its proper divisors (4741366666715).

14224100000133 is an equidigital number, since it uses as much as digits as its factorization.

14224100000133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4741366666714.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14224100000133 its reverse (33100000142241), we get a palindrome (47324100142374).

The spelling of 14224100000133 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred thirty-three", and thus it is an aban number.