Base | Representation |
---|---|
bin | 1100111011111110001001… |
… | …0101111111000001011011 |
3 | 1212100211202021100002210001 |
4 | 3032333202111333001123 |
5 | 3331023120114143120 |
6 | 50130340445233431 |
7 | 2665452511112152 |
oct | 316774225770133 |
9 | 55324667302701 |
10 | 14224434131035 |
11 | 4594604267107 |
12 | 171895a262877 |
13 | 7c24874a110b |
14 | 3726756b6599 |
15 | 19a024519e0a |
hex | cefe257f05b |
14224434131035 has 24 divisors (see below), whose sum is σ = 17509061741184. Its totient is φ = 11093569119360.
The previous prime is 14224434130967. The next prime is 14224434131081. The reversal of 14224434131035 is 53013143442241.
It is not a de Polignac number, because 14224434131035 - 221 = 14224432033883 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14224434130985 and 14224434131003.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3340054 + ... + 6293236.
It is an arithmetic number, because the mean of its divisors is an integer number (729544239216).
Almost surely, 214224434131035 is an apocalyptic number.
14224434131035 is a deficient number, since it is larger than the sum of its proper divisors (3284627610149).
14224434131035 is an equidigital number, since it uses as much as digits as its factorization.
14224434131035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2953795 (or 2953752 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 14224434131035 its reverse (53013143442241), we get a palindrome (67237577573276).
The spelling of 14224434131035 in words is "fourteen trillion, two hundred twenty-four billion, four hundred thirty-four million, one hundred thirty-one thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •