1422513005441 has 4 divisors (see below), whose sum is σ = 1551832369584. Its totient is φ = 1293193641300.

The previous prime is 1422513005413. The next prime is 1422513005449. The reversal of 1422513005441 is 1445003152241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1422513005441 - 2⁶ = 1422513005377 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1422513005398 and 1422513005407.

It is not an unprimeable number, because it can be changed into a prime (1422513005449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64659682055 + ... + 64659682076.

It is an arithmetic number, because the mean of its divisors is an integer number (387958092396).

Almost surely, 2^{1422513005441} is an apocalyptic number.

1422513005441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1422513005441 is a deficient number, since it is larger than the sum of its proper divisors (129319364143).

1422513005441 is a wasteful number, since it uses less digits than its factorization.

1422513005441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129319364142.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1422513005441 its reverse (1445003152241), we get a palindrome (2867516157682).

The spelling of 1422513005441 in words is "one trillion, four hundred twenty-two billion, five hundred thirteen million, five thousand, four hundred forty-one".