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14225420113 = 108013131701
BaseRepresentation
bin11010011111110011…
…01010111101010001
31100201101122012211121
431033321222331101
5213113201420423
610311324042241
71012343035012
oct151771527521
940641565747
1014225420113
11603a973753
122910093381
131459226668
1498d3d5009
15583d0e45d
hex34fe6af51

14225420113 has 4 divisors (see below), whose sum is σ = 14225659828. Its totient is φ = 14225180400.

The previous prime is 14225420107. The next prime is 14225420117. The reversal of 14225420113 is 31102452241.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 8539053649 + 5686366464 = 92407^2 + 75408^2 .

It is a cyclic number.

It is not a de Polignac number, because 14225420113 - 221 = 14223322961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14225420117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42163 + ... + 173863.

It is an arithmetic number, because the mean of its divisors is an integer number (3556414957).

Almost surely, 214225420113 is an apocalyptic number.

It is an amenable number.

14225420113 is a deficient number, since it is larger than the sum of its proper divisors (239715).

14225420113 is a wasteful number, since it uses less digits than its factorization.

14225420113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239714.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 14225420113 its reverse (31102452241), we get a palindrome (45327872354).

The spelling of 14225420113 in words is "fourteen billion, two hundred twenty-five million, four hundred twenty thousand, one hundred thirteen".

Divisors: 1 108013 131701 14225420113