Search a number
-
+
14226460433 = 33154077949
BaseRepresentation
bin11010011111111011…
…01000111100010001
31100201110121001212222
431033331220330101
5213113433213213
610311402230425
71012354630013
oct151775507421
940643531788
1014226460433
116040514319
1229104b5415
1314594cc033
1498d5c61b3
15583e67808
hex34ff68f11

14226460433 has 8 divisors (see below), whose sum is σ = 14273875200. Its totient is φ = 14179073040.

The previous prime is 14226460427. The next prime is 14226460439. The reversal of 14226460433 is 33406462241.

It is an interprime number because it is at equal distance from previous prime (14226460427) and next prime (14226460439).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14226460433 - 210 = 14226459409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14226460393 and 14226460402.

It is not an unprimeable number, because it can be changed into a prime (14226460439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1785743 + ... + 1793691.

It is an arithmetic number, because the mean of its divisors is an integer number (1784234400).

Almost surely, 214226460433 is an apocalyptic number.

It is an amenable number.

14226460433 is a deficient number, since it is larger than the sum of its proper divisors (47414767).

14226460433 is an equidigital number, since it uses as much as digits as its factorization.

14226460433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13687.

The product of its (nonzero) digits is 82944, while the sum is 35.

The spelling of 14226460433 in words is "fourteen billion, two hundred twenty-six million, four hundred sixty thousand, four hundred thirty-three".

Divisors: 1 331 5407 7949 1789717 2631119 42980243 14226460433