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14230001011 = 17837058883
BaseRepresentation
bin11010100000010110…
…01001010101110011
31100201201020221122111
431100023021111303
5213120340013021
610312010150151
71012430004262
oct152013112563
940651227574
1014230001011
116042512416
122911722357
13145a16b755
1498dc685d9
155844168e1
hex3502c9573

14230001011 has 4 divisors (see below), whose sum is σ = 15067059912. Its totient is φ = 13392942112.

The previous prime is 14230001003. The next prime is 14230001017. The reversal of 14230001011 is 11010003241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14230001011 - 23 = 14230001003 is a prime.

It is a super-2 number, since 2×142300010112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14230000982 and 14230001000.

It is not an unprimeable number, because it can be changed into a prime (14230001017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418529425 + ... + 418529458.

It is an arithmetic number, because the mean of its divisors is an integer number (3766764978).

Almost surely, 214230001011 is an apocalyptic number.

14230001011 is a deficient number, since it is larger than the sum of its proper divisors (837058901).

14230001011 is an equidigital number, since it uses as much as digits as its factorization.

14230001011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 837058900.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14230001011 its reverse (11010003241), we get a palindrome (25240004252).

The spelling of 14230001011 in words is "fourteen billion, two hundred thirty million, one thousand, eleven".

Divisors: 1 17 837058883 14230001011