Base | Representation |
---|---|
bin | 11010100000010110… |
… | …01001010101110011 |
3 | 1100201201020221122111 |
4 | 31100023021111303 |
5 | 213120340013021 |
6 | 10312010150151 |
7 | 1012430004262 |
oct | 152013112563 |
9 | 40651227574 |
10 | 14230001011 |
11 | 6042512416 |
12 | 2911722357 |
13 | 145a16b755 |
14 | 98dc685d9 |
15 | 5844168e1 |
hex | 3502c9573 |
14230001011 has 4 divisors (see below), whose sum is σ = 15067059912. Its totient is φ = 13392942112.
The previous prime is 14230001003. The next prime is 14230001017. The reversal of 14230001011 is 11010003241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14230001011 - 23 = 14230001003 is a prime.
It is a super-2 number, since 2×142300010112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14230000982 and 14230001000.
It is not an unprimeable number, because it can be changed into a prime (14230001017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418529425 + ... + 418529458.
It is an arithmetic number, because the mean of its divisors is an integer number (3766764978).
Almost surely, 214230001011 is an apocalyptic number.
14230001011 is a deficient number, since it is larger than the sum of its proper divisors (837058901).
14230001011 is an equidigital number, since it uses as much as digits as its factorization.
14230001011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 837058900.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 14230001011 its reverse (11010003241), we get a palindrome (25240004252).
The spelling of 14230001011 in words is "fourteen billion, two hundred thirty million, one thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •