Base | Representation |
---|---|
bin | 1000010010000111100… |
… | …0101111000001010011 |
3 | 111121022022011000210100 |
4 | 2010201320233001103 |
5 | 4312413411112210 |
6 | 145212311103443 |
7 | 13165246536621 |
oct | 2044170570123 |
9 | 447268130710 |
10 | 142302441555 |
11 | 553940225aa |
12 | 236b4971b83 |
13 | 1055a8b0551 |
14 | 6c5d334511 |
15 | 3a7ce265c0 |
hex | 2121e2f053 |
142302441555 has 24 divisors (see below), whose sum is σ = 246690879552. Its totient is φ = 75884385024.
The previous prime is 142302441503. The next prime is 142302441577. The reversal of 142302441555 is 555144203241.
142302441555 is a `hidden beast` number, since 1 + 4 + 230 + 2 + 4 + 415 + 5 + 5 = 666.
It is not a de Polignac number, because 142302441555 - 27 = 142302441427 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 129382 + ... + 548948.
It is an arithmetic number, because the mean of its divisors is an integer number (10278786648).
Almost surely, 2142302441555 is an apocalyptic number.
142302441555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
142302441555 is a deficient number, since it is larger than the sum of its proper divisors (104388437997).
142302441555 is a wasteful number, since it uses less digits than its factorization.
142302441555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 427115 (or 427112 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 36.
Adding to 142302441555 its reverse (555144203241), we get a palindrome (697446644796).
The spelling of 142302441555 in words is "one hundred forty-two billion, three hundred two million, four hundred forty-one thousand, five hundred fifty-five".
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