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1423122011555 = 5284624402311
BaseRepresentation
bin10100101101011000101…
…011101001010110100011
312001001022211010200110012
4110231120223221112203
5141304023213332210
63005435003355135
7204550201336316
oct24553053512643
95031284120405
101423122011555
114a95a7302852
121ab988822aab
13a427a04570a
144cc453b897d
1527043021305
hex14b58ae95a3

1423122011555 has 4 divisors (see below), whose sum is σ = 1707746413872. Its totient is φ = 1138497609240.

The previous prime is 1423122011537. The next prime is 1423122011573. The reversal of 1423122011555 is 5551102213241.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1423122011537) and next prime (1423122011573).

It is not a de Polignac number, because 1423122011555 - 220 = 1423120962979 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142312201151 + ... + 142312201160.

It is an arithmetic number, because the mean of its divisors is an integer number (426936603468).

Almost surely, 21423122011555 is an apocalyptic number.

1423122011555 is a deficient number, since it is larger than the sum of its proper divisors (284624402317).

1423122011555 is an equidigital number, since it uses as much as digits as its factorization.

1423122011555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 284624402316.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 1423122011555 its reverse (5551102213241), we get a palindrome (6974224224796).

The spelling of 1423122011555 in words is "one trillion, four hundred twenty-three billion, one hundred twenty-two million, eleven thousand, five hundred fifty-five".

Divisors: 1 5 284624402311 1423122011555