Base | Representation |
---|---|
bin | 11010100000100000… |
… | …00110100000010010 |
3 | 1100201210200221200102 |
4 | 31100100012200102 |
5 | 213121203100424 |
6 | 10312054052402 |
7 | 1012444024613 |
oct | 152020064022 |
9 | 40653627612 |
10 | 14231300114 |
11 | 604321a459 |
12 | 291204a102 |
13 | 145a504b55 |
14 | 9900c5c0a |
15 | 5845c17ae |
hex | 350406812 |
14231300114 has 4 divisors (see below), whose sum is σ = 21346950174. Its totient is φ = 7115650056.
The previous prime is 14231300113. The next prime is 14231300119. The reversal of 14231300114 is 41100313241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10015005625 + 4216294489 = 100075^2 + 64933^2 .
It is not an unprimeable number, because it can be changed into a prime (14231300113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3557825027 + ... + 3557825030.
Almost surely, 214231300114 is an apocalyptic number.
14231300114 is a deficient number, since it is larger than the sum of its proper divisors (7115650060).
14231300114 is an equidigital number, since it uses as much as digits as its factorization.
14231300114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7115650059.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 14231300114 its reverse (41100313241), we get a palindrome (55331613355).
The spelling of 14231300114 in words is "fourteen billion, two hundred thirty-one million, three hundred thousand, one hundred fourteen".
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