Base | Representation |
---|---|
bin | 100000010111000010110010… |
… | …000101010000001000111101 |
3 | 200122220202102212110101110022 |
4 | 200113002302011100020331 |
5 | 122123241424123312113 |
6 | 1222405213103221525 |
7 | 41656232436105311 |
oct | 4027026205201075 |
9 | 618822385411408 |
10 | 142321024041533 |
11 | 41391009851967 |
12 | 13b66926ba78a5 |
13 | 6154a7968531c |
14 | 27205351adb41 |
15 | 116c16a773908 |
hex | 8170b215023d |
142321024041533 has 4 divisors (see below), whose sum is σ = 143441662026240. Its totient is φ = 141200386056828.
The previous prime is 142321024041503. The next prime is 142321024041541. The reversal of 142321024041533 is 335140420123241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142321024041533 is a prime.
It is a super-2 number, since 2×1423210240415332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142321024041493 and 142321024041502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142321024041503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560318992163 + ... + 560318992416.
It is an arithmetic number, because the mean of its divisors is an integer number (35860415506560).
Almost surely, 2142321024041533 is an apocalyptic number.
It is an amenable number.
142321024041533 is a deficient number, since it is larger than the sum of its proper divisors (1120637984707).
142321024041533 is a wasteful number, since it uses less digits than its factorization.
142321024041533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1120637984706.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 142321024041533 its reverse (335140420123241), we get a palindrome (477461444164774).
The spelling of 142321024041533 in words is "one hundred forty-two trillion, three hundred twenty-one billion, twenty-four million, forty-one thousand, five hundred thirty-three".
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