Base | Representation |
---|---|
bin | 100000010111000011101110… |
… | …000111000010100011010010 |
3 | 200122220212001001111110010011 |
4 | 200113003232013002203102 |
5 | 122123301004433034442 |
6 | 1222405501041025134 |
7 | 41656266415244455 |
oct | 4027035607024322 |
9 | 618825031443104 |
10 | 142322031143122 |
11 | 41391486286226 |
12 | 13b66b683251aa |
13 | 6154baa20aa1c |
14 | 27205ccc4949c |
15 | 116c1c8da9117 |
hex | 8170ee1c28d2 |
142322031143122 has 4 divisors (see below), whose sum is σ = 213483046714686. Its totient is φ = 71161015571560.
The previous prime is 142322031143081. The next prime is 142322031143143. The reversal of 142322031143122 is 221341130223241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 133515506021881 + 8806525121241 = 11554891^2 + 2967579^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35580507785779 + ... + 35580507785782.
Almost surely, 2142322031143122 is an apocalyptic number.
142322031143122 is a deficient number, since it is larger than the sum of its proper divisors (71161015571564).
142322031143122 is an equidigital number, since it uses as much as digits as its factorization.
142322031143122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71161015571563.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 142322031143122 its reverse (221341130223241), we get a palindrome (363663161366363).
The spelling of 142322031143122 in words is "one hundred forty-two trillion, three hundred twenty-two billion, thirty-one million, one hundred forty-three thousand, one hundred twenty-two".
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