Base | Representation |
---|---|
bin | 100000010111000100111011… |
… | …110011001000010011100111 |
3 | 200122220222101220002012122101 |
4 | 200113010323303020103213 |
5 | 122123311142120443123 |
6 | 1222410234241312531 |
7 | 41656343623062004 |
oct | 4027047363102347 |
9 | 618828356065571 |
10 | 142323334546663 |
11 | 41391a94a98636 |
12 | 13b67270935747 |
13 | 6155057267c1a |
14 | 27206b3db48ab |
15 | 116c25351caad |
hex | 81713bcc84e7 |
142323334546663 has 4 divisors (see below), whose sum is σ = 142323569863240. Its totient is φ = 142323099230088.
The previous prime is 142323334546639. The next prime is 142323334546669. The reversal of 142323334546663 is 366645433323241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142323334546663 - 225 = 142323300992231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142323334546669) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116748720 + ... + 117961477.
It is an arithmetic number, because the mean of its divisors is an integer number (35580892465810).
Almost surely, 2142323334546663 is an apocalyptic number.
142323334546663 is a deficient number, since it is larger than the sum of its proper divisors (235316577).
142323334546663 is an equidigital number, since it uses as much as digits as its factorization.
142323334546663 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 235316576.
The product of its digits is 67184640, while the sum is 55.
The spelling of 142323334546663 in words is "one hundred forty-two trillion, three hundred twenty-three billion, three hundred thirty-four million, five hundred forty-six thousand, six hundred sixty-three".
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