Base | Representation |
---|---|
bin | 11010100000101000… |
… | …11011000101101001 |
3 | 1100201212211111201012 |
4 | 31100110123011221 |
5 | 213122000324001 |
6 | 10312134233305 |
7 | 1012456453523 |
oct | 152024330551 |
9 | 40655744635 |
10 | 14232433001 |
11 | 6043923626 |
12 | 29124b5835 |
13 | 145a8106b7 |
14 | 9902dca13 |
15 | 5847472bb |
hex | 35051b169 |
14232433001 has 4 divisors (see below), whose sum is σ = 14240609604. Its totient is φ = 14224256400.
The previous prime is 14232432989. The next prime is 14232433003. The reversal of 14232433001 is 10033423241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 10033423241 = 97 ⋅103437353.
It can be written as a sum of positive squares in 2 ways, for example, as 1395769600 + 12836663401 = 37360^2 + 113299^2 .
It is a cyclic number.
It is not a de Polignac number, because 14232433001 - 26 = 14232432937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14232433003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4085690 + ... + 4089171.
It is an arithmetic number, because the mean of its divisors is an integer number (3560152401).
Almost surely, 214232433001 is an apocalyptic number.
It is an amenable number.
14232433001 is a deficient number, since it is larger than the sum of its proper divisors (8176603).
14232433001 is an equidigital number, since it uses as much as digits as its factorization.
14232433001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8176602.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 14232433001 its reverse (10033423241), we get a palindrome (24265856242).
The spelling of 14232433001 in words is "fourteen billion, two hundred thirty-two million, four hundred thirty-three thousand, one".
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