Base | Representation |
---|---|
bin | 1100111100011011111110… |
… | …0011100001010001000011 |
3 | 1212101121102020120021110011 |
4 | 3033012333203201101003 |
5 | 3331141014221124303 |
6 | 50134143131445351 |
7 | 2666155066266640 |
oct | 317067743412103 |
9 | 55347366507404 |
10 | 14232440411203 |
11 | 4597a42633983 |
12 | 171a4135b6857 |
13 | 7c31621028c1 |
14 | 372bd4b36dc7 |
15 | 19a34235616d |
hex | cf1bf8e1443 |
14232440411203 has 4 divisors (see below), whose sum is σ = 16265646184240. Its totient is φ = 12199234638168.
The previous prime is 14232440411197. The next prime is 14232440411221. The reversal of 14232440411203 is 30211404423241.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14232440411203 - 213 = 14232440403011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14232440411503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1016602886508 + ... + 1016602886521.
It is an arithmetic number, because the mean of its divisors is an integer number (4066411546060).
Almost surely, 214232440411203 is an apocalyptic number.
14232440411203 is a deficient number, since it is larger than the sum of its proper divisors (2033205773037).
14232440411203 is an equidigital number, since it uses as much as digits as its factorization.
14232440411203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2033205773036.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14232440411203 its reverse (30211404423241), we get a palindrome (44443844834444).
The spelling of 14232440411203 in words is "fourteen trillion, two hundred thirty-two billion, four hundred forty million, four hundred eleven thousand, two hundred three".
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