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14233053353 = 82317294111
BaseRepresentation
bin11010100000101101…
…10010100010101001
31100201221000000200012
431100112302202221
5213122130201403
610312155421305
71012464646241
oct152026624251
940657000605
1014233053353
116044207712
122912754835
13145a999b7c
14990420b21
1558481aed8
hex3505b28a9

14233053353 has 4 divisors (see below), whose sum is σ = 14250348288. Its totient is φ = 14215758420.

The previous prime is 14233053337. The next prime is 14233053377. The reversal of 14233053353 is 35335033241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35335033241 = 161392189419.

It is a cyclic number.

It is not a de Polignac number, because 14233053353 - 24 = 14233053337 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14233053053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8646233 + ... + 8647878.

It is an arithmetic number, because the mean of its divisors is an integer number (3562587072).

Almost surely, 214233053353 is an apocalyptic number.

It is an amenable number.

14233053353 is a deficient number, since it is larger than the sum of its proper divisors (17294935).

14233053353 is an equidigital number, since it uses as much as digits as its factorization.

14233053353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17294934.

The product of its (nonzero) digits is 48600, while the sum is 32.

Adding to 14233053353 its reverse (35335033241), we get a palindrome (49568086594).

The spelling of 14233053353 in words is "fourteen billion, two hundred thirty-three million, fifty-three thousand, three hundred fifty-three".

Divisors: 1 823 17294111 14233053353