Base | Representation |
---|---|
bin | 11010100000101110… |
… | …11100001110110010 |
3 | 1100201221022200220200 |
4 | 31100113130032302 |
5 | 213122201132424 |
6 | 10312203220030 |
7 | 1012466260134 |
oct | 152027341662 |
9 | 40657280820 |
10 | 14233224114 |
11 | 6044313a3a |
12 | 2912817616 |
13 | 145aa29805 |
14 | 990467054 |
15 | 5848518c9 |
hex | 3505dc3b2 |
14233224114 has 12 divisors (see below), whose sum is σ = 30838652286. Its totient is φ = 4744408032.
The previous prime is 14233224107. The next prime is 14233224191. The reversal of 14233224114 is 41142233241.
14233224114 is a `hidden beast` number, since 1 + 423 + 3 + 224 + 1 + 14 = 666.
14233224114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 12247184889 + 1986039225 = 110667^2 + 44565^2 .
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 395367319 + ... + 395367354.
Almost surely, 214233224114 is an apocalyptic number.
14233224114 is an abundant number, since it is smaller than the sum of its proper divisors (16605428172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14233224114 is a wasteful number, since it uses less digits than its factorization.
14233224114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 790734681 (or 790734678 counting only the distinct ones).
The product of its digits is 4608, while the sum is 27.
Adding to 14233224114 its reverse (41142233241), we get a palindrome (55375457355).
The spelling of 14233224114 in words is "fourteen billion, two hundred thirty-three million, two hundred twenty-four thousand, one hundred fourteen".
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