Base | Representation |
---|---|
bin | 1100111100011110111101… |
… | …1010011101110110111001 |
3 | 1212101200111012102111121111 |
4 | 3033013233122131312321 |
5 | 3331144140244004223 |
6 | 50134354533240321 |
7 | 2666214016150540 |
oct | 317075732356671 |
9 | 55350435374544 |
10 | 14233243344313 |
11 | 4598314898464 |
12 | 171a5b84930a1 |
13 | 7c325c571856 |
14 | 372c6d627157 |
15 | 19a38caac30d |
hex | cf1ef69ddb9 |
14233243344313 has 32 divisors (see below), whose sum is σ = 17780571857664. Its totient is φ = 11114062036992.
The previous prime is 14233243344293. The next prime is 14233243344317. The reversal of 14233243344313 is 31344334233241.
It is a cyclic number.
It is not a de Polignac number, because 14233243344313 - 237 = 14095804390841 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14233243344317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7524895 + ... + 9224452.
It is an arithmetic number, because the mean of its divisors is an integer number (555642870552).
Almost surely, 214233243344313 is an apocalyptic number.
It is an amenable number.
14233243344313 is a deficient number, since it is larger than the sum of its proper divisors (3547328513351).
14233243344313 is a wasteful number, since it uses less digits than its factorization.
14233243344313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16749601.
The product of its digits is 746496, while the sum is 40.
Adding to 14233243344313 its reverse (31344334233241), we get a palindrome (45577577577554).
The spelling of 14233243344313 in words is "fourteen trillion, two hundred thirty-three billion, two hundred forty-three million, three hundred forty-four thousand, three hundred thirteen".
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