1423330254401 has 4 divisors (see below), whose sum is σ = 1552723913904. Its totient is φ = 1293936594900.

The previous prime is 1423330254397. The next prime is 1423330254481. The reversal of 1423330254401 is 1044520333241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1423330254401 - 2² = 1423330254397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1423330254481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64696829735 + ... + 64696829756.

It is an arithmetic number, because the mean of its divisors is an integer number (388180978476).

Almost surely, 2^{1423330254401} is an apocalyptic number.

1423330254401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1423330254401 is a deficient number, since it is larger than the sum of its proper divisors (129393659503).

1423330254401 is a wasteful number, since it uses less digits than its factorization.

1423330254401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129393659502.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 1423330254401 its reverse (1044520333241), we get a palindrome (2467850587642).

The spelling of 1423330254401 in words is "one trillion, four hundred twenty-three billion, three hundred thirty million, two hundred fifty-four thousand, four hundred one".