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14233403113 = 107832915971
BaseRepresentation
bin11010100000110000…
…00111111011101001
31100201221122210110021
431100120013323221
5213122222344423
610312211120441
71012500634036
oct152030077351
940657583407
1014233403113
116044426476
1229128a3121
13145aa90127
149904b238d
1558488995d
hex350607ee9

14233403113 has 8 divisors (see below), whose sum is σ = 14369050080. Its totient is φ = 14097804960.

The previous prime is 14233403081. The next prime is 14233403117. The reversal of 14233403113 is 31130433241.

14233403113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14233403113 - 25 = 14233403081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14233403117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 883218 + ... + 899188.

It is an arithmetic number, because the mean of its divisors is an integer number (1796131260).

Almost surely, 214233403113 is an apocalyptic number.

It is an amenable number.

14233403113 is a deficient number, since it is larger than the sum of its proper divisors (135646967).

14233403113 is a wasteful number, since it uses less digits than its factorization.

14233403113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24407.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 14233403113 its reverse (31130433241), we get a palindrome (45363836354).

The spelling of 14233403113 in words is "fourteen billion, two hundred thirty-three million, four hundred three thousand, one hundred thirteen".

Divisors: 1 107 8329 15971 891203 1708897 133022459 14233403113