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142342011002113 = 1357718976404613
BaseRepresentation
bin100000010111010110010101…
…000000001001110100000001
3200122222202121111010110002121
4200113112111000021310001
5122124112414304031423
61222423003410444241
741660604504244306
oct4027262500116401
9618882544113077
10142342011002113
11413999a93a8a8a
1213b6aa03593681
136156a42682cb0
1427215665ab0ad
15116c997e9745d
hex817595009d01

142342011002113 has 8 divisors (see below), whose sum is σ = 153557066136488. Its totient is φ = 131164908678144.

The previous prime is 142342011002089. The next prime is 142342011002123. The reversal of 142342011002113 is 311200110243241.

It can be written as a sum of positive squares in 4 ways, for example, as 77860275879409 + 64481735122704 = 8823847^2 + 8030052^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 142342011002113 - 237 = 142204572048641 is a prime.

It is a super-2 number, since 2×1423420110021132 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142342011002123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9488194806 + ... + 9488209807.

It is an arithmetic number, because the mean of its divisors is an integer number (19194633267061).

Almost surely, 2142342011002113 is an apocalyptic number.

142342011002113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

142342011002113 is a deficient number, since it is larger than the sum of its proper divisors (11215055134375).

142342011002113 is a wasteful number, since it uses less digits than its factorization.

142342011002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18976405203.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 142342011002113 its reverse (311200110243241), we get a palindrome (453542121245354).

The spelling of 142342011002113 in words is "one hundred forty-two trillion, three hundred forty-two billion, eleven million, two thousand, one hundred thirteen".

Divisors: 1 13 577 7501 18976404613 246693259969 10949385461701 142342011002113