Base | Representation |
---|---|
bin | 1000010010010011001… |
… | …0010111010010001011 |
3 | 111121102200201021220100 |
4 | 2010210302113102023 |
5 | 4313013340244430 |
6 | 145221210100443 |
7 | 13166410261224 |
oct | 2044462272213 |
9 | 447380637810 |
10 | 142351103115 |
11 | 55409539771 |
12 | 2370911a723 |
13 | 105679ba680 |
14 | 6c659a024b |
15 | 3a82339960 |
hex | 2124c9748b |
142351103115 has 24 divisors (see below), whose sum is σ = 265722060240. Its totient is φ = 70080542784.
The previous prime is 142351103093. The next prime is 142351103129. The reversal of 142351103115 is 511301153241.
142351103115 is a `hidden beast` number, since 1 + 4 + 235 + 110 + 311 + 5 = 666.
It is not a de Polignac number, because 142351103115 - 219 = 142350578827 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 121667025 + ... + 121668194.
It is an arithmetic number, because the mean of its divisors is an integer number (11071752510).
Almost surely, 2142351103115 is an apocalyptic number.
142351103115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
142351103115 is a deficient number, since it is larger than the sum of its proper divisors (123370957125).
142351103115 is a wasteful number, since it uses less digits than its factorization.
142351103115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243335243 (or 243335240 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 142351103115 its reverse (511301153241), we get a palindrome (653652256356).
The spelling of 142351103115 in words is "one hundred forty-two billion, three hundred fifty-one million, one hundred three thousand, one hundred fifteen".
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