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142365201440551 = 314592425852921
BaseRepresentation
bin100000010111101011111011…
…010000101001111100100111
3200200001222110200000210002221
4200113223323100221330213
5122130002413032044201
61222441400510213211
741662355256566065
oct4027537320517447
9620058420023087
10142365201440551
11413a881983a691
1213b733b5ab4207
136158c9a02c30b
1427227264ad035
15116d3a3d734a1
hex817afb429f27

142365201440551 has 4 divisors (see below), whose sum is σ = 146957627293504. Its totient is φ = 137772775587600.

The previous prime is 142365201440543. The next prime is 142365201440587. The reversal of 142365201440551 is 155044102563241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142365201440551 - 23 = 142365201440543 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142365201440498 and 142365201440507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142365201440521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2296212926430 + ... + 2296212926491.

It is an arithmetic number, because the mean of its divisors is an integer number (36739406823376).

Almost surely, 2142365201440551 is an apocalyptic number.

142365201440551 is a deficient number, since it is larger than the sum of its proper divisors (4592425852953).

142365201440551 is an equidigital number, since it uses as much as digits as its factorization.

142365201440551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4592425852952.

The product of its (nonzero) digits is 576000, while the sum is 43.

The spelling of 142365201440551 in words is "one hundred forty-two trillion, three hundred sixty-five billion, two hundred one million, four hundred forty thousand, five hundred fifty-one".

Divisors: 1 31 4592425852921 142365201440551