Base | Representation |
---|---|
bin | 100000011000001100110101… |
… | …110010000011000011100001 |
3 | 200200012100200200102120200010 |
4 | 200120030311302003003201 |
5 | 122131042303002323131 |
6 | 1222505523434515133 |
7 | 41665046130150540 |
oct | 4030146562030341 |
9 | 620170620376603 |
10 | 142400543011041 |
11 | 41411805178687 |
12 | 13b7a219895aa9 |
13 | 615c40cc473c3 |
14 | 272431a0d0157 |
15 | 116e2718c4b46 |
hex | 818335c830e1 |
142400543011041 has 8 divisors (see below), whose sum is σ = 216991303635904. Its totient is φ = 81371738863440.
The previous prime is 142400543011007. The next prime is 142400543011079. The reversal of 142400543011041 is 140110345004241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 142400543011041 - 233 = 142391953076449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (142400543011541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3390489119290 + ... + 3390489119331.
It is an arithmetic number, because the mean of its divisors is an integer number (27123912954488).
Almost surely, 2142400543011041 is an apocalyptic number.
It is an amenable number.
142400543011041 is a deficient number, since it is larger than the sum of its proper divisors (74590760624863).
142400543011041 is an equidigital number, since it uses as much as digits as its factorization.
142400543011041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6780978238631.
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 142400543011041 its reverse (140110345004241), we get a palindrome (282510888015282).
The spelling of 142400543011041 in words is "one hundred forty-two trillion, four hundred billion, five hundred forty-three million, eleven thousand, forty-one".
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