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14240133111 = 34746711037
BaseRepresentation
bin11010100001100011…
…10010111111110111
31100202102022201021110
431100301302333313
5213130433224421
610313011250103
71012612064031
oct152061627767
940672281243
1014240133111
116048202856
122914ba9933
13145c2a8489
14991344c51
15585268a76
hex350c72ff7

14240133111 has 4 divisors (see below), whose sum is σ = 18986844152. Its totient is φ = 9493422072.

The previous prime is 14240133097. The next prime is 14240133143. The reversal of 14240133111 is 11133104241.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14240133111 - 210 = 14240132087 is a prime.

It is a super-3 number, since 3×142401331113 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14240133211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373355516 + ... + 2373355521.

It is an arithmetic number, because the mean of its divisors is an integer number (4746711038).

Almost surely, 214240133111 is an apocalyptic number.

14240133111 is a deficient number, since it is larger than the sum of its proper divisors (4746711041).

14240133111 is an equidigital number, since it uses as much as digits as its factorization.

14240133111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4746711040.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 14240133111 its reverse (11133104241), we get a palindrome (25373237352).

The spelling of 14240133111 in words is "fourteen billion, two hundred forty million, one hundred thirty-three thousand, one hundred eleven".

Divisors: 1 3 4746711037 14240133111