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14240304115 = 531725433533
BaseRepresentation
bin11010100001100100…
…11100101111110011
31100202102122101211221
431100302130233303
5213131004212430
610313015045511
71012613405422
oct152062345763
940672571757
1014240304115
11604830a284
122915070897
13145c33826b
1499138b2b9
1558529e57a
hex350c9cbf3

14240304115 has 16 divisors (see below), whose sum is σ = 17153866368. Its totient is φ = 11348626816.

The previous prime is 14240304103. The next prime is 14240304121. The reversal of 14240304115 is 51140304241.

It is a cyclic number.

It is not a de Polignac number, because 14240304115 - 217 = 14240173043 is a prime.

It is a super-2 number, since 2×142403041152 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14240304115.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4028889 + ... + 4032421.

It is an arithmetic number, because the mean of its divisors is an integer number (1072116648).

Almost surely, 214240304115 is an apocalyptic number.

14240304115 is a deficient number, since it is larger than the sum of its proper divisors (2913562253).

14240304115 is a wasteful number, since it uses less digits than its factorization.

14240304115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6398.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 14240304115 its reverse (51140304241), we get a palindrome (65380608356).

The spelling of 14240304115 in words is "fourteen billion, two hundred forty million, three hundred four thousand, one hundred fifteen".

Divisors: 1 5 317 1585 2543 3533 12715 17665 806131 1119961 4030655 5599805 8984419 44922095 2848060823 14240304115