Base | Representation |
---|---|
bin | 1100111100111001011010… |
… | …1010111011011010000101 |
3 | 1212102100211002100121221120 |
4 | 3033032112222323122011 |
5 | 3331303211133001041 |
6 | 50141531322104153 |
7 | 2666555003261154 |
oct | 317162652733205 |
9 | 55370732317846 |
10 | 14240344422021 |
11 | 45a03291aa223 |
12 | 171ba5a64b059 |
13 | 7c3b217a7993 |
14 | 37334477559b |
15 | 19a6561e0366 |
hex | cf396abb685 |
14240344422021 has 8 divisors (see below), whose sum is σ = 18989916916320. Its totient is φ = 9492167437872.
The previous prime is 14240344421951. The next prime is 14240344422043. The reversal of 14240344422021 is 12022444304241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14240344422021 - 27 = 14240344421893 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14240344422061) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348853726 + ... + 348894543.
It is an arithmetic number, because the mean of its divisors is an integer number (2373739614540).
Almost surely, 214240344422021 is an apocalyptic number.
It is an amenable number.
14240344422021 is a deficient number, since it is larger than the sum of its proper divisors (4749572494299).
14240344422021 is an equidigital number, since it uses as much as digits as its factorization.
14240344422021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 697755075.
The product of its (nonzero) digits is 49152, while the sum is 33.
Adding to 14240344422021 its reverse (12022444304241), we get a palindrome (26262788726262).
The spelling of 14240344422021 in words is "fourteen trillion, two hundred forty billion, three hundred forty-four million, four hundred twenty-two thousand, twenty-one".
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