Base | Representation |
---|---|
bin | 11010100001101011… |
… | …00101010010110011 |
3 | 1100202111012010122122 |
4 | 31100311211102303 |
5 | 213131212004210 |
6 | 10313044424455 |
7 | 1012623366326 |
oct | 152065452263 |
9 | 40674163578 |
10 | 14241125555 |
11 | 6048820458 |
12 | 29153a812b |
13 | 145c565117 |
14 | 9915227bd |
15 | 5853b2b55 |
hex | 350d654b3 |
14241125555 has 16 divisors (see below), whose sum is σ = 17767512000. Its totient is φ = 10944743040.
The previous prime is 14241125551. The next prime is 14241125593. The reversal of 14241125555 is 55552114241.
14241125555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14241125555 - 22 = 14241125551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14241125551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 217916 + ... + 275625.
It is an arithmetic number, because the mean of its divisors is an integer number (1110469500).
Almost surely, 214241125555 is an apocalyptic number.
14241125555 is a deficient number, since it is larger than the sum of its proper divisors (3526386445).
14241125555 is a wasteful number, since it uses less digits than its factorization.
14241125555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 493774.
The product of its digits is 40000, while the sum is 35.
Adding to 14241125555 its reverse (55552114241), we get a palindrome (69793239796).
The spelling of 14241125555 in words is "fourteen billion, two hundred forty-one million, one hundred twenty-five thousand, five hundred fifty-five".
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