Base | Representation |
---|---|
bin | 1000010010100001101… |
… | …1000101110111010001 |
3 | 111121120221111211102020 |
4 | 2010220123011313101 |
5 | 4313130000030223 |
6 | 145231225442053 |
7 | 13201050654543 |
oct | 2045033056721 |
9 | 447527454366 |
10 | 142412111313 |
11 | 5543aa1906a |
12 | 23725640329 |
13 | 1057752b4b4 |
14 | 6c6db21693 |
15 | 3a8788b1e3 |
hex | 21286c5dd1 |
142412111313 has 4 divisors (see below), whose sum is σ = 189882815088. Its totient is φ = 94941407540.
The previous prime is 142412111299. The next prime is 142412111329. The reversal of 142412111313 is 313111214241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142412111313 - 28 = 142412111057 is a prime.
It is not an unprimeable number, because it can be changed into a prime (142412111333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23735351883 + ... + 23735351888.
It is an arithmetic number, because the mean of its divisors is an integer number (47470703772).
Almost surely, 2142412111313 is an apocalyptic number.
It is an amenable number.
142412111313 is a deficient number, since it is larger than the sum of its proper divisors (47470703775).
142412111313 is an equidigital number, since it uses as much as digits as its factorization.
142412111313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47470703774.
The product of its digits is 576, while the sum is 24.
Adding to 142412111313 its reverse (313111214241), we get a palindrome (455523325554).
The spelling of 142412111313 in words is "one hundred forty-two billion, four hundred twelve million, one hundred eleven thousand, three hundred thirteen".
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