Base | Representation |
---|---|
bin | 1000010010100001110… |
… | …0100101010110100111 |
3 | 111121120222020200221101 |
4 | 2010220130211112213 |
5 | 4313130100034224 |
6 | 145231242100531 |
7 | 13201054204054 |
oct | 2045034452647 |
9 | 447528220841 |
10 | 142412502439 |
11 | 55440165a09 |
12 | 237257aa747 |
13 | 1057763752c |
14 | 6c6dbc402b |
15 | 3a87917044 |
hex | 21287255a7 |
142412502439 has 4 divisors (see below), whose sum is σ = 142415965224. Its totient is φ = 142409039656.
The previous prime is 142412502437. The next prime is 142412502451. The reversal of 142412502439 is 934205214241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142412502439 - 21 = 142412502437 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142412502398 and 142412502407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142412502437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668952 + ... + 1752205.
It is an arithmetic number, because the mean of its divisors is an integer number (35603991306).
Almost surely, 2142412502439 is an apocalyptic number.
142412502439 is a deficient number, since it is larger than the sum of its proper divisors (3462785).
142412502439 is an equidigital number, since it uses as much as digits as its factorization.
142412502439 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3462784.
The product of its (nonzero) digits is 69120, while the sum is 37.
The spelling of 142412502439 in words is "one hundred forty-two billion, four hundred twelve million, five hundred two thousand, four hundred thirty-nine".
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