1424133344113 has 4 divisors (see below), whose sum is σ = 1424354936560. Its totient is φ = 1423911751668.

The previous prime is 1424133344093. The next prime is 1424133344149. The reversal of 1424133344113 is 3114433314241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1424133344113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1424133744113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110786583 + ... + 110799436.

It is an arithmetic number, because the mean of its divisors is an integer number (356088734140).

Almost surely, 2^{1424133344113} is an apocalyptic number.

It is an amenable number.

1424133344113 is a deficient number, since it is larger than the sum of its proper divisors (221592447).

1424133344113 is an equidigital number, since it uses as much as digits as its factorization.

1424133344113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221592446.

The product of its digits is 41472, while the sum is 34.

Adding to 1424133344113 its reverse (3114433314241), we get a palindrome (4538566658354).

The spelling of 1424133344113 in words is "one trillion, four hundred twenty-four billion, one hundred thirty-three million, three hundred forty-four thousand, one hundred thirteen".