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142433203553 = 1311087276363
BaseRepresentation
bin1000010010100110101…
…1100011010101100001
3111121122102012102112022
42010221223203111201
54313200400003203
6145233301511225
713201425153134
oct2045153432541
9447572172468
10142433203553
1155450914a73
1223730712515
131057ba04b04
146c7285221b
153a89655a38
hex2129ae3561

142433203553 has 4 divisors (see below), whose sum is σ = 143520480048. Its totient is φ = 141345927060.

The previous prime is 142433203513. The next prime is 142433203579. The reversal of 142433203553 is 355302334241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142433203553 - 210 = 142433202529 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142433203513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 543638051 + ... + 543638312.

It is an arithmetic number, because the mean of its divisors is an integer number (35880120012).

Almost surely, 2142433203553 is an apocalyptic number.

It is an amenable number.

142433203553 is a deficient number, since it is larger than the sum of its proper divisors (1087276495).

142433203553 is a wasteful number, since it uses less digits than its factorization.

142433203553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1087276494.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 142433203553 its reverse (355302334241), we get a palindrome (497735537794).

The spelling of 142433203553 in words is "one hundred forty-two billion, four hundred thirty-three million, two hundred three thousand, five hundred fifty-three".

Divisors: 1 131 1087276363 142433203553