Base | Representation |
---|---|
bin | 1100111101000100100100… |
… | …1111011100110011011011 |
3 | 1212102122112212201001102010 |
4 | 3033101021033130303123 |
5 | 3331330330111343233 |
6 | 50143144503041003 |
7 | 3000022152204204 |
oct | 317211117346333 |
9 | 55378485631363 |
10 | 14243340340443 |
11 | 45a1626332065 |
12 | 1720555a40163 |
13 | 7c41ab390486 |
14 | 37354a5d85ab |
15 | 19a77e229b63 |
hex | cf4493dccdb |
14243340340443 has 4 divisors (see below), whose sum is σ = 18991120453928. Its totient is φ = 9495560226960.
The previous prime is 14243340340423. The next prime is 14243340340483. The reversal of 14243340340443 is 34404304334241.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-14243340340443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14243340340423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373890056738 + ... + 2373890056743.
It is an arithmetic number, because the mean of its divisors is an integer number (4747780113482).
Almost surely, 214243340340443 is an apocalyptic number.
14243340340443 is a deficient number, since it is larger than the sum of its proper divisors (4747780113485).
14243340340443 is an equidigital number, since it uses as much as digits as its factorization.
14243340340443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4747780113484.
The product of its (nonzero) digits is 663552, while the sum is 39.
Adding to 14243340340443 its reverse (34404304334241), we get a palindrome (48647644674684).
The spelling of 14243340340443 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty million, three hundred forty thousand, four hundred forty-three".
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