Search a number
-
+
14243340340443 = 34747780113481
BaseRepresentation
bin1100111101000100100100…
…1111011100110011011011
31212102122112212201001102010
43033101021033130303123
53331330330111343233
650143144503041003
73000022152204204
oct317211117346333
955378485631363
1014243340340443
1145a1626332065
121720555a40163
137c41ab390486
1437354a5d85ab
1519a77e229b63
hexcf4493dccdb

14243340340443 has 4 divisors (see below), whose sum is σ = 18991120453928. Its totient is φ = 9495560226960.

The previous prime is 14243340340423. The next prime is 14243340340483. The reversal of 14243340340443 is 34404304334241.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-14243340340443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14243340340423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2373890056738 + ... + 2373890056743.

It is an arithmetic number, because the mean of its divisors is an integer number (4747780113482).

Almost surely, 214243340340443 is an apocalyptic number.

14243340340443 is a deficient number, since it is larger than the sum of its proper divisors (4747780113485).

14243340340443 is an equidigital number, since it uses as much as digits as its factorization.

14243340340443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4747780113484.

The product of its (nonzero) digits is 663552, while the sum is 39.

Adding to 14243340340443 its reverse (34404304334241), we get a palindrome (48647644674684).

The spelling of 14243340340443 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty million, three hundred forty thousand, four hundred forty-three".

Divisors: 1 3 4747780113481 14243340340443