Base | Representation |
---|---|
bin | 1100111101000100100100… |
… | …1111011100110011000111 |
3 | 1212102122112212201001101101 |
4 | 3033101021033130303013 |
5 | 3331330330111343143 |
6 | 50143144503040531 |
7 | 3000022152204145 |
oct | 317211117346307 |
9 | 55378485631341 |
10 | 14243340340423 |
11 | 45a1626332047 |
12 | 1720555a40147 |
13 | 7c41ab39046c |
14 | 37354a5d8595 |
15 | 19a77e229b4d |
hex | cf4493dccc7 |
14243340340423 has 2 divisors, whose sum is σ = 14243340340424. Its totient is φ = 14243340340422.
The previous prime is 14243340340421. The next prime is 14243340340483. The reversal of 14243340340423 is 32404304334241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14243340340423 - 21 = 14243340340421 is a prime.
Together with 14243340340421, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14243340340421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121670170211 + 7121670170212.
It is an arithmetic number, because the mean of its divisors is an integer number (7121670170212).
Almost surely, 214243340340423 is an apocalyptic number.
14243340340423 is a deficient number, since it is larger than the sum of its proper divisors (1).
14243340340423 is an equidigital number, since it uses as much as digits as its factorization.
14243340340423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 331776, while the sum is 37.
Adding to 14243340340423 its reverse (32404304334241), we get a palindrome (46647644674664).
The spelling of 14243340340423 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty million, three hundred forty thousand, four hundred twenty-three".
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