Base | Representation |
---|---|
bin | 1000010010100111010… |
… | …0100001011101001111 |
3 | 111121122120121220022112 |
4 | 2010221310201131033 |
5 | 4313202000231101 |
6 | 145233424134235 |
7 | 13201454146121 |
oct | 2045164413517 |
9 | 447576556275 |
10 | 142435555151 |
11 | 5545218083a |
12 | 2373146737b |
13 | 1057c3492a6 |
14 | 6c72ca5211 |
15 | 3a8996c6bb |
hex | 2129d2174f |
142435555151 has 4 divisors (see below), whose sum is σ = 142441833600. Its totient is φ = 142429276704.
The previous prime is 142435555147. The next prime is 142435555193. The reversal of 142435555151 is 151555534241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142435555151 - 22 = 142435555147 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142435555099 and 142435555108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142435555111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3105071 + ... + 3150608.
It is an arithmetic number, because the mean of its divisors is an integer number (35610458400).
Almost surely, 2142435555151 is an apocalyptic number.
142435555151 is a deficient number, since it is larger than the sum of its proper divisors (6278449).
142435555151 is an equidigital number, since it uses as much as digits as its factorization.
142435555151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6278448.
The product of its digits is 300000, while the sum is 41.
The spelling of 142435555151 in words is "one hundred forty-two billion, four hundred thirty-five million, five hundred fifty-five thousand, one hundred fifty-one".
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