Base | Representation |
---|---|
bin | 1000010010101000011… |
… | …1000110100000101001 |
3 | 111121122220210100012022 |
4 | 2010222013012200221 |
5 | 4313204222104023 |
6 | 145234120354225 |
7 | 13201543432331 |
oct | 2045207064051 |
9 | 447586710168 |
10 | 142440425513 |
11 | 554549a7a31 |
12 | 23733015975 |
13 | 10580363069 |
14 | 6c737b20c1 |
15 | 3a8a0d07c8 |
hex | 212a1c6829 |
142440425513 has 4 divisors (see below), whose sum is σ = 142457572608. Its totient is φ = 142423278420.
The previous prime is 142440425467. The next prime is 142440425527. The reversal of 142440425513 is 315524044241.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 142440425513 - 214 = 142440409129 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (142440425573) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8561081 + ... + 8577702.
It is an arithmetic number, because the mean of its divisors is an integer number (35614393152).
Almost surely, 2142440425513 is an apocalyptic number.
It is an amenable number.
142440425513 is a deficient number, since it is larger than the sum of its proper divisors (17147095).
142440425513 is an equidigital number, since it uses as much as digits as its factorization.
142440425513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17147094.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 142440425513 its reverse (315524044241), we get a palindrome (457964469754).
The spelling of 142440425513 in words is "one hundred forty-two billion, four hundred forty million, four hundred twenty-five thousand, five hundred thirteen".
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