1424421324341 has 4 divisors (see below), whose sum is σ = 1424425118400. Its totient is φ = 1424417530284.

The previous prime is 1424421324323. The next prime is 1424421324343. The reversal of 1424421324341 is 1434231244241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1424421324341 is a prime.

It is a super-2 number, since 2×1424421324341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1424421324343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1263311 + ... + 2108268.

It is an arithmetic number, because the mean of its divisors is an integer number (356106279600).

Almost surely, 2^{1424421324341} is an apocalyptic number.

It is an amenable number.

1424421324341 is a deficient number, since it is larger than the sum of its proper divisors (3794059).

1424421324341 is an equidigital number, since it uses as much as digits as its factorization.

1424421324341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3794058.

The product of its digits is 73728, while the sum is 35.

Adding to 1424421324341 its reverse (1434231244241), we get a palindrome (2858652568582).

The spelling of 1424421324341 in words is "one trillion, four hundred twenty-four billion, four hundred twenty-one million, three hundred twenty-four thousand, three hundred forty-one".