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14245245113 = 111295022283
BaseRepresentation
bin11010100010001010…
…10011000010111001
31100202202221102121212
431101011103002321
5213133240320423
610313313012505
71013003404601
oct152105230271
940682842555
1014245245113
116050084550
122916854135
131460378228
14991cb5c01
15585928578
hex3511530b9

14245245113 has 4 divisors (see below), whose sum is σ = 15540267408. Its totient is φ = 12950222820.

The previous prime is 14245245107. The next prime is 14245245127. The reversal of 14245245113 is 31154254241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14245245113 - 28 = 14245244857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14245245113.

It is not an unprimeable number, because it can be changed into a prime (14245245173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647511131 + ... + 647511152.

It is an arithmetic number, because the mean of its divisors is an integer number (3885066852).

Almost surely, 214245245113 is an apocalyptic number.

It is an amenable number.

14245245113 is a deficient number, since it is larger than the sum of its proper divisors (1295022295).

14245245113 is a wasteful number, since it uses less digits than its factorization.

14245245113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1295022294.

The product of its digits is 19200, while the sum is 32.

Adding to 14245245113 its reverse (31154254241), we get a palindrome (45399499354).

The spelling of 14245245113 in words is "fourteen billion, two hundred forty-five million, two hundred forty-five thousand, one hundred thirteen".

Divisors: 1 11 1295022283 14245245113