Base | Representation |
---|---|
bin | 1100111101001011101111… |
… | …0110010011111001111011 |
3 | 1212102211111212202220010212 |
4 | 3033102323312103321323 |
5 | 3331343244330131420 |
6 | 50144103351101335 |
7 | 3000120620512304 |
oct | 317227366237173 |
9 | 55384455686125 |
10 | 14245263130235 |
11 | 45a2422733535 |
12 | 17209b197184b |
13 | 7c4426843207 |
14 | 37368db157ab |
15 | 19a842e3a3c5 |
hex | cf4bbd93e7b |
14245263130235 has 32 divisors (see below), whose sum is σ = 18091703289600. Its totient is φ = 10737897667200.
The previous prime is 14245263130187. The next prime is 14245263130237. The reversal of 14245263130235 is 53203136254241.
It is not a de Polignac number, because 14245263130235 - 212 = 14245263126139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14245263130192 and 14245263130201.
It is not an unprimeable number, because it can be changed into a prime (14245263130237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20256260 + ... + 20947710.
It is an arithmetic number, because the mean of its divisors is an integer number (565365727800).
Almost surely, 214245263130235 is an apocalyptic number.
14245263130235 is a deficient number, since it is larger than the sum of its proper divisors (3846440159365).
14245263130235 is a wasteful number, since it uses less digits than its factorization.
14245263130235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 692651.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 14245263130235 its reverse (53203136254241), we get a palindrome (67448399384476).
The spelling of 14245263130235 in words is "fourteen trillion, two hundred forty-five billion, two hundred sixty-three million, one hundred thirty thousand, two hundred thirty-five".
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