1424782104131 has 4 divisors (see below), whose sum is σ = 1437390795432. Its totient is φ = 1412173412832.

The previous prime is 1424782104127. The next prime is 1424782104133. The reversal of 1424782104131 is 1314012874241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1424782104131 - 2² = 1424782104127 is a prime.

It is a super-2 number, since 2×1424782104131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1424782104133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6304345481 + ... + 6304345706.

It is an arithmetic number, because the mean of its divisors is an integer number (359347698858).

Almost surely, 2^{1424782104131} is an apocalyptic number.

1424782104131 is a deficient number, since it is larger than the sum of its proper divisors (12608691301).

1424782104131 is a wasteful number, since it uses less digits than its factorization.

1424782104131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12608691300.

The product of its (nonzero) digits is 43008, while the sum is 38.

Adding to 1424782104131 its reverse (1314012874241), we get a palindrome (2738794978372).

The spelling of 1424782104131 in words is "one trillion, four hundred twenty-four billion, seven hundred eighty-two million, one hundred four thousand, one hundred thirty-one".