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1425386913131 = 1975020363849
BaseRepresentation
bin10100101111011111101…
…011100011110101101011
312001021011122221121022202
4110233133223203311223
5141323143022210011
63010451432210415
7204660262566026
oct24573753436553
95037148847282
101425386913131
114aa559830935
121b02bb239a0b
13a454b34c06c
144cdbc10c1bd
1527126cad23b
hex14bdfae3d6b

1425386913131 has 4 divisors (see below), whose sum is σ = 1500407277000. Its totient is φ = 1350366549264.

The previous prime is 1425386913101. The next prime is 1425386913133. The reversal of 1425386913131 is 1313196835241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1425386913131 - 238 = 1150509006187 is a prime.

It is a super-2 number, since 2×14253869131312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1425386913133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37510181906 + ... + 37510181943.

It is an arithmetic number, because the mean of its divisors is an integer number (375101819250).

Almost surely, 21425386913131 is an apocalyptic number.

1425386913131 is a deficient number, since it is larger than the sum of its proper divisors (75020363869).

1425386913131 is an equidigital number, since it uses as much as digits as its factorization.

1425386913131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75020363868.

The product of its digits is 466560, while the sum is 47.

The spelling of 1425386913131 in words is "one trillion, four hundred twenty-five billion, three hundred eighty-six million, nine hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 19 75020363849 1425386913131