Base | Representation |
---|---|
bin | 1100111101101101000010… |
… | …0110000100110101100111 |
3 | 1212110200120210012100021220 |
4 | 3033123100212010311213 |
5 | 3332020100442132333 |
6 | 50152142315311423 |
7 | 3000555251326536 |
oct | 317332046046547 |
9 | 55420523170256 |
10 | 14254201130343 |
11 | 45a6199a28289 |
12 | 172268714b573 |
13 | 7c521c4c6185 |
14 | 373c9abcc31d |
15 | 19abb796b8b3 |
hex | cf6d0984d67 |
14254201130343 has 16 divisors (see below), whose sum is σ = 19093102479360. Its totient is φ = 9459060420384.
The previous prime is 14254201130341. The next prime is 14254201130381. The reversal of 14254201130343 is 34303110245241.
It is not a de Polignac number, because 14254201130343 - 21 = 14254201130341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14254201130341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4370193 + ... + 6899781.
It is an arithmetic number, because the mean of its divisors is an integer number (1193318904960).
Almost surely, 214254201130343 is an apocalyptic number.
14254201130343 is a deficient number, since it is larger than the sum of its proper divisors (4838901349017).
14254201130343 is a wasteful number, since it uses less digits than its factorization.
14254201130343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2538238.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 14254201130343 its reverse (34303110245241), we get a palindrome (48557311375584).
The spelling of 14254201130343 in words is "fourteen trillion, two hundred fifty-four billion, two hundred one million, one hundred thirty thousand, three hundred forty-three".
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