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142543133151 = 347514377717
BaseRepresentation
bin1000010011000000111…
…0111001100111011111
3111121221002001102120220
42010300032321213133
54313412020230101
6145252230012423
713204231432446
oct2046016714737
9447832042526
10142543133151
11554a7978781
12237614a7113
1310598714103
146c832a9d5d
153a9411c636
hex21303b99df

142543133151 has 4 divisors (see below), whose sum is σ = 190057510872. Its totient is φ = 95028755432.

The previous prime is 142543133149. The next prime is 142543133177. The reversal of 142543133151 is 151331345241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151331345241 = 350443781747.

It is a cyclic number.

It is not a de Polignac number, because 142543133151 - 21 = 142543133149 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142543133141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23757188856 + ... + 23757188861.

It is an arithmetic number, because the mean of its divisors is an integer number (47514377718).

Almost surely, 2142543133151 is an apocalyptic number.

142543133151 is a deficient number, since it is larger than the sum of its proper divisors (47514377721).

142543133151 is an equidigital number, since it uses as much as digits as its factorization.

142543133151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47514377720.

The product of its digits is 21600, while the sum is 33.

Adding to 142543133151 its reverse (151331345241), we get a palindrome (293874478392).

The spelling of 142543133151 in words is "one hundred forty-two billion, five hundred forty-three million, one hundred thirty-three thousand, one hundred fifty-one".

Divisors: 1 3 47514377717 142543133151