1425444535 has 4 divisors (see below), whose sum is σ = 1710533448. Its totient is φ = 1140355624.

The previous prime is 1425444533. The next prime is 1425444547. The reversal of 1425444535 is 5354445241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5354445241 = 23 ⋅232801967.

It is a cyclic number.

It is not a de Polignac number, because 1425444535 - 2¹ = 1425444533 is a prime.

It is a super-2 number, since 2×1425444535² = 4063784244722732450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1425444494 and 1425444503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1425444533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142544449 + ... + 142544458.

It is an arithmetic number, because the mean of its divisors is an integer number (427633362).

Almost surely, 2^1425444535 is an apocalyptic number.

1425444535 is a deficient number, since it is larger than the sum of its proper divisors (285088913).

1425444535 is an equidigital number, since it uses as much as digits as its factorization.

1425444535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 285088912.

The product of its digits is 192000, while the sum is 37.

The square root of 1425444535 is about 37755.0597271412. The cubic root of 1425444535 is about 1125.4255601529.

Adding to 1425444535 its reverse (5354445241), we get a palindrome (6779889776).

The spelling of 1425444535 in words is "one billion, four hundred twenty-five million, four hundred forty-four thousand, five hundred thirty-five".